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In , more specifically in functional analysis, a Banach space (, ) is a complete normed vector space. Thus, a Banach space is a vector space with a metric that allows the computation of vector length and distance between vectors and is complete in the sense that a of vectors always converges to a well-defined limit that is within the space.

Banach spaces are named after the Polish mathematician , who introduced this concept and studied it systematically in 1920–1922 along with Hans Hahn and . Maurice René Fréchet was the first to use the term "Banach space" and Banach in turn then coined the term "Fréchet space". Banach spaces originally grew out of the study of by , Fréchet, and earlier in the century. Banach spaces play a central role in functional analysis. In other areas of analysis, the spaces under study are often Banach spaces.


Definition
A Banach space is a complete (X, \|{\cdot}\|). A normed space is a pairIt is common to read instead of the more technically correct but (usually) pedantic especially if the norm is well known (for example, such as with ) or when there is no particular need to choose any one (equivalent) norm over any other (especially in the more abstract theory of topological vector spaces), in which case this norm (if needed) is often automatically assumed to be denoted by \|{\cdot}\|. However, in situations where emphasis is placed on the norm, it is common to see (X, \|{\cdot}\|) written instead of X. The technically correct definition of normed spaces as pairs (X, \|{\cdot}\|) may also become important in the context of where the distinction between the categories of normed spaces, , , TVSs, topological spaces, etc. is usually important. (X, \|{\cdot}\|) consisting of a X over a scalar field \mathbb{K} (where \mathbb{K} is commonly \Reals or \Complex) together with a distinguishedThis means that if the norm \|{\cdot}\| is replaced with a different norm \|{\cdot}\|' on X, then (X, \|{\cdot}\|) is the same normed space as (X, \|{\cdot}\|'), not even if the norms are equivalent. However, equivalence of norms on a given vector space does form an equivalence relation. norm \|{\cdot}\| : X \to \Reals. Like all norms, this norm induces a translation invariantA metric D on a vector space X is said to be translation invariant if D(x, y) = D(x + z, y + z) for all vectors x, y, z \in X. This happens if and only if D(x, y) = D(x - y, 0) for all vectors x, y \in X. A metric that is induced by a norm is always translation invariant. distance function, called the canonical or (norm) induced metric, defined for all vectors x, y \in X byBecause \|{-z}\| = \|z\| for all z \in X, it is always true that d(x, y) := \|y - x\| = \|x - y\| for all x, y \in X. So the order of x and y in this definition does not matter. d(x, y) := \|y - x\| = \|x - y\|. This makes X into a (X, d). A sequence x_1, x_2, \ldots is called or or if for every real r > 0, there exists some index N such that d(x_n, x_m) = \|x_n - x_m\| < r whenever m and n are greater than N. The normed space (X, \|{\cdot}\|) is called a Banach space and the canonical metric d is called a complete metric if (X, d) is a complete metric space, which by definition means for every x_1, x_2, \ldots in (X, d), there exists some x \in X such that \lim_{n \to \infty} x_n = x \; \text{ in } (X, d), where because \|x_n - x\| = d(x_n, x), this sequence's convergence to x can equivalently be expressed as \lim_{n \to \infty} \|x_n - x\| = 0 \; \text{ in } \Reals.

The norm \|{\cdot}\| of a normed space (X, \|{\cdot}\|) is called a if (X, \|{\cdot}\|) is a Banach space.


L-semi-inner product
For any normed space (X, \|{\cdot}\|), there exists an L-semi-inner product \langle\cdot, \cdot\rangle on X such that \|x\| = \sqrt{\langle x, x \rangle} for all x \in X. In general, there may be infinitely many L-semi-inner products that satisfy this condition and the proof of the existence of L-semi-inner products relies on the non-constructive Hahn–Banach theorem. L-semi-inner products are a generalization of , which are what fundamentally distinguish from all other Banach spaces. This shows that all normed spaces (and hence all Banach spaces) can be considered as being generalizations of (pre-)Hilbert spaces.


Characterization in terms of series
The vector space structure allows one to relate the behavior of Cauchy sequences to that of converging series of vectors. A normed space X is a Banach space if and only if each absolutely convergent series in X converges to a value that lies within X,see Theorem 1.3.9, p. 20 in . symbolically \sum_{n=1}^{\infty} \|v_n\| < \infty \implies \sum_{n=1}^{\infty} v_n\text{ converges in } X.


Topology
The canonical metric d of a normed space (X, \|{\cdot}\|) induces the usual \tau_d on X, which is referred to as the canonical or norm induced . Every normed space is automatically assumed to carry this topology, unless indicated otherwise. With this topology, every Banach space is a , although there exist normed spaces that are Baire but not Banach. The norm \|{\cdot}\| : X \to \Reals is always a continuous function with respect to the topology that it induces.

The open and closed balls of radius r > 0 centered at a point x \in X are, respectively, the sets B_r(x) := \{z \in X \mid \|z - x\| < r\} \qquad \text{ and } \qquad C_r(x) := \{z \in X \mid \|z - x\| \leq r\}. Any such ball is a and bounded subset of X, but a ball/neighborhood exists if and only if X is finite-dimensional. In particular, no infinite–dimensional normed space can be locally compact or have the . If x_0 is a vector and s \neq 0 is a scalar, then x_0 + s\,B_r(x) = B_{|s| r}(x_0 + s x) \qquad \text{ and } \qquad x_0 + s\,C_r(x) = C_{|s| r}(x_0 + s x). Using s = 1 shows that the norm-induced topology is translation invariant, which means that for any x \in X and S \subseteq X, the subset S is (respectively, ) in X if and only if its translation x + S := \{x + s \mid s \in S\} is open (respectively, closed). Consequently, the norm induced topology is completely determined by any neighbourhood basis at the origin. Some common neighborhood bases at the origin include \{B_r(0) \mid r > 0\}, \qquad \{C_r(0) \mid r > 0\}, \qquad \{B_{r_n}(0) \mid n \in \N\}, \qquad \text{ and } \qquad \{C_{r_n}(0) \mid n \in \N\}, where r_1, r_2, \ldots can be any sequence of positive real numbers that converges to 0 in \R (common choices are r_n := \tfrac{1}{n} or r_n := 1/2^n). So, for example, any open subset U of X can be written as a union U = \bigcup_{x \in I} B_{r_x}(x) = \bigcup_{x \in I} x + B_{r_x}(0) = \bigcup_{x \in I} x + r_x\,B_1(0) indexed by some subset I \subseteq U, where each r_x may be chosen from the aforementioned sequence r_1, r_2, \ldots. (The open balls can also be replaced with closed balls, although the indexing set I and radii r_x may then also need to be replaced). Additionally, I can always be chosen to be if X is a , which by definition means that X contains some countable .


Homeomorphism classes of separable Banach spaces
All finite–dimensional normed spaces are separable Banach spaces and any two Banach spaces of the same finite dimension are linearly homeomorphic. Every separable infinite–dimensional is linearly isometrically isomorphic to the separable Hilbert sequence space \ell^2(\N) with its usual norm \|{\cdot}\|_2.

The Anderson–Kadec theorem states that every infinite–dimensional separable Fréchet space is to the \prod_{i \in \N} \Reals of countably many copies of \Reals (this homeomorphism need not be a ). Thus all infinite–dimensional separable Fréchet spaces are homeomorphic to each other (or said differently, their topology is unique a homeomorphism). Since every Banach space is a Fréchet space, this is also true of all infinite–dimensional separable Banach spaces, including \ell^2(\N). In fact, \ell^2(\N) is even to its own \{x \in \ell^2(\N) \mid \|x\|_2 = 1\}, which stands in sharp contrast to finite–dimensional spaces (the \Reals^2 is not homeomorphic to the , for instance).

This pattern in homeomorphism classes extends to generalizations of metrizable (locally Euclidean) topological manifolds known as , which are that are around every point, locally homeomorphic to some open subset of a given Banach space (metric and metric Fréchet manifolds are defined similarly). For example, every open subset U of a Banach space X is canonically a metric Banach manifold modeled on X since the U \to X is an local homeomorphism. Using Hilbert space , David Henderson showed in 1969 that every metric manifold modeled on a separable infinite–dimensional Banach (or Fréchet) space can be topologically embedded as an of \ell^2(\N) and, consequently, also admits a unique making it into a C^\infty .


Compact and convex subsets
There is a compact subset S of \ell^2(\N) whose \operatorname{co}(S) is closed and thus also compact.Let H be the separable \ell^2(\N) of square-summable sequences with the usual norm \|{\cdot}\|_2, and let e_n = (0, \ldots, 0, 1, 0, \ldots, 0) be the standard orthonormal basis (that is, each e_n has zeros in every position except for a 1 in the nth-position). The closed set S = \{0\} \cup \{\tfrac{1}{n} e_n \mid n = 1, 2, \ldots\} is compact (because it is sequentially compact) but its convex hull \operatorname{co} S is a closed set because the point h := \sum_{n=1}^{\infty} \tfrac{1}{2^n} \tfrac{1}{n} e_n belongs to the closure of \operatorname{co} S in H but h \not\in\operatorname{co} S (since every point z=(z_1,z_2,\ldots) \in \operatorname{co} S is a finite convex combination of elements of S and so z_n = 0 for all but finitely many coordinates, which is not true of h). However, like in all complete Hausdorff locally convex spaces, the convex hull K := \overline{\operatorname{co}} S of this compact subset is compact. The vector subspace X := \operatorname{span} S = \operatorname{span} \{e_1, e_2, \ldots\} is a pre-Hilbert space when endowed with the substructure that the Hilbert space H induces on it, but X is not complete and h \not\in C := K \cap X (since h \not\in X). The closed convex hull of S in X (here, "closed" means with respect to X, and not to H as before) is equal to K \cap X, which is not compact (because it is not a complete subset). This shows that in a Hausdorff locally convex space that is not complete, the closed convex hull of a compact subset might to be compact (although it will be precompact/totally bounded). However, like in all Banach spaces, the convex hull \overline{\operatorname{co}} S of this (and every other) compact subset will be compact. In a normed space that is not complete then it is in general guaranteed that \overline{\operatorname{co}} S will be compact whenever S is; an example can even be found in a (non-complete) pre-Hilbert vector subspace of \ell^2(\N).


As a topological vector space
This norm-induced topology also makes (X, \tau_d) into what is known as a topological vector space (TVS), which by definition is a vector space endowed with a topology making the operations of addition and scalar multiplication continuous. It is emphasized that the TVS (X, \tau_d) is a vector space together with a certain type of topology; that is to say, when considered as a TVS, it is associated with particular norm or metric (both of which are "forgotten"). This Hausdorff TVS (X, \tau_d) is even locally convex because the set of all open balls centered at the origin forms a neighbourhood basis at the origin consisting of convex open sets. This TVS is also , which by definition refers to any TVS whose topology is induced by some (possibly unknown) norm. Normable TVSs are characterized by being Hausdorff and having a bounded neighborhood of the origin. All Banach spaces are , which means that every is neighborhood of the origin (all closed balls centered at the origin are barrels, for example) and guarantees that the Banach–Steinhaus theorem holds.


Comparison of complete metrizable vector topologies
The open mapping theorem implies that when \tau_1 and \tau_2 are topologies on X that make both (X, \tau_1) and (X, \tau_2) into (for example, Banach or Fréchet spaces), if one topology is finer or coarser than the other, then they must be equal (that is, if \tau_1 \subseteq \tau_2 or \tau_2 \subseteq \tau_1 then \tau_1 = \tau_2). So, for example, if (X, p) and (X, q) are Banach spaces with topologies \tau_p and \tau_q, and if one of these spaces has some open ball that is also an open subset of the other space (or, equivalently, if one of p : (X, \tau_q) \to \Reals or q : (X, \tau_p) \to \Reals is continuous), then their topologies are identical and the norms p and q are .


Completeness

Complete norms and equivalent norms
Two norms, p and q, on a vector space X are said to be if they induce the same topology; this happens if and only if there exist real numbers c,C > 0 such that c\,q(x) \leq p(x) \leq C\,q(x) for all x \in X. If p and q are two equivalent norms on a vector space X then (X, p) is a Banach space if and only if (X, q) is a Banach space. See this footnote for an example of a continuous norm on a Banach space that is equivalent to that Banach space's given norm.Let (C(0,), |{\cdot}\|_{\infty}) denote the Banach space of continuous functions with the supremum norm and let \tau_{\infty} denote the topology on C(0,) induced by \|{\cdot}\|_{\infty}. The vector space C(0,) can be identified (via the ) as a proper vector subspace X of the (L^1(0,), \|{\cdot}\|_1), which satisfies \|f\|_1 \leq \|f\|_{\infty} for all f \in X. Let p denote the restriction of \|{\cdot}\|_1 to X, which makes this map p : X \to \R a norm on X (in general, the restriction of any norm to any vector subspace will necessarily again be a norm). The normed space (X, p) is a Banach space since its completion is the proper superset (L^1(0,), \|{\cdot}\|_1). Because p \leq \|{\cdot}\|_{\infty} holds on X, the map p : (X, \tau_{\infty}) \to \R is continuous. Despite this, the norm p is equivalent to the norm \|{\cdot}\|_{\infty} (because (X, \|{\cdot}\|_{\infty}) is complete but (X, p) is not). All norms on a finite-dimensional vector space are equivalent and every finite-dimensional normed space is a Banach space.see Corollary 1.4.18, p. 32 in .


Complete norms vs complete metrics
A metric D on a vector space X is induced by a norm on X if and only if D is translation invariant and absolutely homogeneous, which means that D(sx, sy) = |s| D(x, y) for all scalars s and all x, y \in X, in which case the function \|x\| := D(x, 0) defines a norm on X and the canonical metric induced by \|{\cdot}\| is equal to D.

Suppose that (X, \|{\cdot}\|) is a normed space and that \tau is the norm topology induced on X. Suppose that D is metric on X such that the topology that D induces on X is equal to \tau. If D is translation invariant then (X, \|{\cdot}\|) is a Banach space if and only if (X, D) is a complete metric space. If D is translation invariant, then it may be possible for (X, \|{\cdot}\|) to be a Banach space but for (X, D) to be a complete metric space (see this footnoteThe (\R,|\cdot |) is a Banach space where the absolute value is a norm on the real line \R that induces the usual Euclidean topology on \R. Define a metric D : \R \times \R \to \R on \R by D(x, y) =|\arctan(x) - \arctan(y)| for all x, y \in \R. Just like induced metric, the metric D also induces the usual Euclidean topology on \R. However, D is not a complete metric because the sequence x_{\bull} = (x_i)_{i=1}^{\infty} defined by x_i := i is a but it does not converge to any point of \R. As a consequence of not converging, this sequence cannot be a Cauchy sequence in (\R,|\cdot |) (that is, it is not a Cauchy sequence with respect to the norm |\cdot|) because if it was then the fact that (\R,|\cdot |) is a Banach space would imply that it converges (a contradiction). for an example). In contrast, a theorem of Klee,The statement of the theorem is: Let d be metric on a vector space X such that the topology \tau induced by d on X makes (X, \tau) into a topological vector space. If (X, d) is a complete metric space then (X, \tau) is a complete topological vector space. which also applies to all metrizable topological vector spaces, implies that if there exists This metric D is assumed to be translation-invariant. So in particular, this metric D does even have to be induced by a norm. complete metric D on X that induces the norm topology \tau on X, then (X, \|{\cdot}\|) is a Banach space.

A Fréchet space is a locally convex topological vector space whose topology is induced by some translation-invariant complete metric. Every Banach space is a Fréchet space but not conversely; indeed, there even exist Fréchet spaces on which no norm is a continuous function (such as the space of real sequences \R^{\N} = \prod_{i \in \N} \R with the ). However, the topology of every Fréchet space is induced by some family of real-valued (necessarily continuous) maps called , which are generalizations of norms. It is even possible for a Fréchet space to have a topology that is induced by a countable family of (such norms would necessarily be continuous)A norm (or ) p on a topological vector space (X, \tau) is continuous if and only if the topology \tau_p that p induces on X is coarser than \tau (meaning, \tau_p \subseteq \tau), which happens if and only if there exists some open ball B in (X, p) (such as maybe \{x \in X \mid p(x) < 1\} for example) that is open in (X, \tau). but to not be a Banach/ because its topology can not be defined by any norm. An example of such a space is the Fréchet space C^{\infty}(K), whose definition can be found in the article on spaces of test functions and distributions.


Complete norms vs complete topological vector spaces
There is another notion of completeness besides metric completeness and that is the notion of a complete topological vector space (TVS) or TVS-completeness, which uses the theory of . Specifically, the notion of TVS-completeness uses a unique translation-invariant uniformity, called the canonical uniformity, that depends on vector subtraction and the topology \tau that the vector space is endowed with, and so in particular, this notion of TVS completeness is independent of whatever norm induced the topology \tau (and even applies to TVSs that are even metrizable). Every Banach space is a complete TVS. Moreover, a normed space is a Banach space (that is, its norm-induced metric is complete) if and only if it is complete as a topological vector space. If (X, \tau) is a metrizable topological vector space (such as any norm induced topology, for example), then (X, \tau) is a complete TVS if and only if it is a complete TVS, meaning that it is enough to check that every Cauchy in (X, \tau) converges in (X, \tau) to some point of X (that is, there is no need to consider the more general notion of arbitrary Cauchy nets).

If (X, \tau) is a topological vector space whose topology is induced by (possibly unknown) norm (such spaces are called ), then (X, \tau) is a complete topological vector space if and only if X may be assigned a norm \|{\cdot}\| that induces on X the topology \tau and also makes (X, \|{\cdot}\|) into a Banach space. A locally convex topological vector space X is if and only if its strong dual space X'_b is normable, in which case X'_b is a Banach space (X'_b denotes the strong dual space of X, whose topology is a generalization of the -induced topology on the continuous dual space X'; see this footnoteX' denotes the continuous dual space of X. When X' is endowed with the strong dual space topology, also called the topology of uniform convergence on bounded subsets of X, then this is indicated by writing X'_b (sometimes, the subscript \beta is used instead of b). When X is a normed space with norm \|{\cdot}\| then this topology is equal to the topology on X' induced by the . In this way, the strong topology is a generalization of the usual dual norm-induced topology on X'. for more details). If X is a metrizable locally convex TVS, then X is normable if and only if X'_b is a Fréchet–Urysohn space.Gabriyelyan, S.S. "On topological spaces and topological groups with certain local countable networks (2014) This shows that in the category of locally convex TVSs, Banach spaces are exactly those complete spaces that are both metrizable and have metrizable strong dual spaces.


Completions
Every normed space can be embedded onto a dense vector subspace of a Banach space, where this Banach space is called a completion of the normed space. This Hausdorff completion is unique up to isomorphism.

More precisely, for every normed space X, there exists a Banach space Y and a mapping T : X \to Y such that T is an and T(X) is dense in Y. If Z is another Banach space such that there is an isometric isomorphism from X onto a dense subset of Z, then Z is isometrically isomorphic to Y. The Banach space Y is the Hausdorff completion of the normed space X. The underlying metric space for Y is the same as the metric completion of X, with the vector space operations extended from X to Y. The completion of X is sometimes denoted by \widehat{X}.


General theory

Linear operators, isomorphisms
If X and Y are normed spaces over the same \mathbb{K}, the set of all continuous \mathbb{K}-linear maps T : X \to Y is denoted by B(X, Y). In infinite-dimensional spaces, not all linear maps are continuous. A linear mapping from a normed space X to another normed space is continuous if and only if it is on the closed of X. Thus, the vector space B(X, Y) can be given the \|T\| = \sup \{\|Tx\|_Y \mid x\in X,\ \|x\|_X \leq 1\}.

For Y a Banach space, the space B(X, Y) is a Banach space with respect to this norm. In categorical contexts, it is sometimes convenient to restrict the between two Banach spaces to only the ; in that case the space B(X,Y) reappears as a natural .

If X is a Banach space, the space B(X) = B(X, X) forms a unital ; the multiplication operation is given by the composition of linear maps.

If X and Y are normed spaces, they are isomorphic normed spaces if there exists a linear bijection T : X \to Y such that T and its inverse T^{-1} are continuous. If one of the two spaces X or Y is complete (or , , etc.) then so is the other space. Two normed spaces X and Y are isometrically isomorphic if in addition, T is an , that is, \|T(x)\| = \|x\| for every x in X. The Banach–Mazur distance d(X, Y) between two isomorphic but not isometric spaces X and Y gives a measure of how much the two spaces X and Y differ.


Continuous and bounded linear functions and seminorms
Every continuous linear operator is a bounded linear operator and if dealing only with normed spaces then the converse is also true. That is, a between two normed spaces is bounded if and only if it is a continuous function. So in particular, because the scalar field (which is \R or \Complex) is a normed space, a linear functional on a normed space is a bounded linear functional if and only if it is a continuous linear functional. This allows for continuity-related results (like those below) to be applied to Banach spaces. Although boundedness is the same as continuity for linear maps between normed spaces, the term "bounded" is more commonly used when dealing primarily with Banach spaces.

If f : X \to \R is a subadditive function (such as a norm, a sublinear function, or real linear functional), then f is continuous at the origin if and only if f is uniformly continuous on all of X; and if in addition f(0) = 0 then f is continuous if and only if its |f| : X \to [0, \infty) is continuous, which happens if and only if \{x \in X \mid |f(x)| < 1\} is an open subset of X.The fact that \{x \in X \mid |f(x)| < 1\} being open implies that f : X \to \R is continuous simplifies proving continuity because this means that it suffices to show that \{x \in X \mid |f(x) - f(x_0)| < r\} is open for r := 1 and at x_0 := 0 (where f(0) = 0) rather than showing this for real r > 0 and x_0 \in X. And very importantly for applying the Hahn–Banach theorem, a linear functional f is continuous if and only if this is true of its \operatorname{Re} f and moreover, \|\operatorname{Re} f\| = \|f\| and the real part \operatorname{Re} f completely determines f, which is why the Hahn–Banach theorem is often stated only for real linear functionals. Also, a linear functional f on X is continuous if and only if the |f| is continuous, which happens if and only if there exists a continuous seminorm p : X \to \R such that |f| \leq p; this last statement involving the linear functional f and seminorm p is encountered in many versions of the Hahn–Banach theorem.


Basic notions
The Cartesian product X \times Y of two normed spaces is not canonically equipped with a norm. However, several equivalent norms are commonly used, such as \|(x, y)\|_1 = \|x\| + \|y\|, \qquad \|(x, y)\|_\infty = \max(\|x\|, \|y\|) which correspond (respectively) to the and product in the category of Banach spaces and short maps (discussed above). For finite (co)products, these norms give rise to isomorphic normed spaces, and the product X \times Y (or the direct sum X \oplus Y) is complete if and only if the two factors are complete.

If M is a of a normed space X, there is a natural norm on the quotient space X / M, \|x + M\| = \inf\limits_{m \in M} \|x + m\|.

The quotient X / M is a Banach space when X is complete.see pp. 17–19 in . The quotient map from X onto X / M, sending x \in X to its class x + M, is linear, onto, and of norm 1, except when M = X, in which case the quotient is the null space.

The closed linear subspace M of X is said to be a complemented subspace of X if M is the range of a bounded linear projection P : X \to M. In this case, the space X is isomorphic to the direct sum of M and \ker P, the kernel of the projection P.

Suppose that X and Y are Banach spaces and that T \in B(X, Y). There exists a canonical factorization of T as T = T_1 \circ \pi, \quad T : X \overset{\pi} X/\ker T \overset{T_1} Y where the first map \pi is the quotient map, and the second map T_1 sends every class x + \ker T in the quotient to the image T(x) in Y. This is well defined because all elements in the same class have the same image. The mapping T_1 is a linear bijection from X/\ker T onto the range T(X), whose inverse need not be bounded.


Classical spaces
Basic examplessee , pp. 11-12. of Banach spaces include: the L^p and their special cases, the sequence spaces \ell^p that consist of scalar sequences indexed by \N; among them, the space \ell^1 of absolutely summable sequences and the space \ell^2 of square summable sequences; the space c_0 of sequences tending to zero and the space \ell^{\infty} of bounded sequences; the space C(K) of continuous scalar functions on a compact Hausdorff space K, equipped with the max norm, \|f\|_{C(K)} = \max \{ |f(x)| \mid x \in K \}, \quad f \in C(K).

According to the Banach–Mazur theorem, every Banach space is isometrically isomorphic to a subspace of some C(K).see , Th. 9 p. 185. For every separable Banach space X, there is a closed subspace M of \ell^1 such that X := \ell^1 / M.see Theorem 6.1, p. 55 in

Any serves as an example of a Banach space. A Hilbert space H on \mathbb{K} = \Reals, \Complex is complete for a norm of the form \|x\|_H = \sqrt{\langle x, x \rangle}, where \langle \cdot, \cdot \rangle : H \times H \to \mathbb{K} is the inner product, linear in its first argument that satisfies the following: \begin{align} \langle y, x \rangle &= \overline{\langle x, y \rangle}, \quad \text{ for all } x, y \in H \\ \langle x, x \rangle & \geq 0, \quad \text{ for all } x \in H \\ \langle x,x \rangle = 0 \text{ if and only if } x &= 0. \end{align}

For example, the space L^2 is a Hilbert space.

The , the are examples of Banach spaces that are related to L^p spaces and have additional structure. They are important in different branches of analysis, Harmonic analysis and Partial differential equations among others.


Banach algebras
A is a Banach space A over \mathbb{K} = \R or \Complex, together with a structure of algebra over \mathbb{K}, such that the product map A \times A \ni (a, b) \mapsto ab \in A is continuous. An equivalent norm on A can be found so that \|ab\| \leq \|a\| \|b\| for all a, b \in A.


Examples
  • The Banach space C(K) with the pointwise product, is a Banach algebra.
  • The A(\mathbf{D}) consists of functions holomorphic in the open unit disk D \subseteq \Complex and continuous on its closure: \overline{\mathbf{D}}. Equipped with the max norm on \overline{\mathbf{D}}, the disk algebra A(\mathbf{D}) is a closed subalgebra of C\left(\overline{\mathbf{D}}\right).
  • The A(\mathbf{T}) is the algebra of functions on the unit circle \mathbf{T} with absolutely convergent Fourier series. Via the map associating a function on \mathbf{T} to the sequence of its Fourier coefficients, this algebra is isomorphic to the Banach algebra \ell^1(Z), where the product is the convolution of sequences.
  • For every Banach space X, the space B(X) of bounded linear operators on X, with the composition of maps as product, is a Banach algebra.
  • A C*-algebra is a complex Banach algebra A with an involution a \mapsto a^* such that \|a^* a\| = \|a\|^2. The space B(H) of bounded linear operators on a Hilbert space H is a fundamental example of C*-algebra. The Gelfand–Naimark theorem states that every C*-algebra is isometrically isomorphic to a C*-subalgebra of some B(H). The space C(K) of complex continuous functions on a compact Hausdorff space K is an example of commutative C*-algebra, where the involution associates to every function f its complex conjugate \overline{f}.


Dual space
If X is a normed space and \mathbb{K} the underlying field (either the or the ), the continuous dual space is the space of continuous linear maps from X into \mathbb{K}, or continuous linear functionals. The notation for the continuous dual is X' = B(X, \mathbb{K}) in this article.Several books about functional analysis use the notation X^* for the continuous dual, for example , , , , . Since \mathbb{K} is a Banach space (using the as norm), the dual X' is a Banach space, for every normed space X. The Dixmier–Ng theorem characterizes the dual spaces of Banach spaces.

The main tool for proving the existence of continuous linear functionals is the Hahn–Banach theorem.

In particular, every continuous linear functional on a subspace of a normed space can be continuously extended to the whole space, without increasing the norm of the functional.Theorem 1.9.6, p. 75 in An important special case is the following: for every vector x in a normed space X, there exists a continuous linear functional f on X such that f(x) = \|x\|_X, \quad \|f\|_{X'} \leq 1.

When x is not equal to the \mathbf{0} vector, the functional f must have norm one, and is called a norming functional for x.

The Hahn–Banach separation theorem states that two disjoint non-empty in a real Banach space, one of them open, can be separated by a closed . The open convex set lies strictly on one side of the hyperplane, the second convex set lies on the other side but may touch the hyperplane.see also Theorem 2.2.26, p. 179 in

A subset S in a Banach space X is total if the of S is in X. The subset S is total in X if and only if the only continuous linear functional that vanishes on S is the \mathbf{0} functional: this equivalence follows from the Hahn–Banach theorem.

If X is the direct sum of two closed linear subspaces M and N, then the dual X' of X is isomorphic to the direct sum of the duals of M and N.see p. 19 in . If M is a closed linear subspace in X, one can associate the M in the dual, M^{\bot} = \{ x' \in X \mid x'(m) = 0 \text{ for all } m \in M \}.

The orthogonal M^{\bot} is a closed linear subspace of the dual. The dual of M is isometrically isomorphic to X' / M^{\bot}. The dual of X / M is isometrically isomorphic to M^{\bot}.Theorems 1.10.16, 1.10.17 pp.94–95 in

The dual of a separable Banach space need not be separable, but:

When X' is separable, the above criterion for totality can be used for proving the existence of a countable total subset in X.


Weak topologies
The on a Banach space X is the coarsest topology on X for which all elements x' in the continuous dual space X' are continuous. The norm topology is therefore finer than the weak topology. It follows from the Hahn–Banach separation theorem that the weak topology is , and that a norm-closed of a Banach space is also weakly closed.Theorem 2.5.16, p. 216 in . A norm-continuous linear map between two Banach spaces X and Y is also weakly continuous, that is, continuous from the weak topology of X to that of Y.see II.A.8, p. 29 in

If X is infinite-dimensional, there exist linear maps which are not continuous. The space X^* of all linear maps from X to the underlying field \mathbb{K} (this space X^* is called the algebraic dual space, to distinguish it from X' also induces a topology on X which is than the weak topology, and much less used in functional analysis.

On a dual space X', there is a topology weaker than the weak topology of X', called the . It is the coarsest topology on X' for which all evaluation maps x' \in X' \mapsto x'(x), where x ranges over X, are continuous. Its importance comes from the Banach–Alaoglu theorem.

The Banach–Alaoglu theorem can be proved using Tychonoff's theorem about infinite products of compact Hausdorff spaces. When X is separable, the unit ball B' of the dual is a compact in the weak* topology.see Theorem 2.6.23, p. 231 in .


Examples of dual spaces
The dual of c_0 is isometrically isomorphic to \ell^1: for every bounded linear functional f on c_0, there is a unique element y = \{y_n\} \in \ell^1 such that f(x) = \sum_{n \in \N} x_n y_n, \qquad x = \{x_n\} \in c_0, \ \ \text{and} \ \ \|f\|_{(c_0)'} = \|y\|_{\ell_1}.

The dual of \ell^1 is isometrically isomorphic to \ell^{\infty}. The dual of Lebesgue space L^p(0,) is isometrically isomorphic to L^q(0,) when 1 \leq p < \infty and \frac{1}{p} + \frac{1}{q} = 1.

For every vector y in a Hilbert space H, the mapping x \in H \to f_y(x) = \langle x, y \rangle

defines a continuous linear functional f_y on H.The Riesz representation theorem states that every continuous linear functional on H is of the form f_y for a uniquely defined vector y in H. The mapping y \in H \to f_y is an isometric bijection from H onto its dual H'. When the scalars are real, this map is an isometric isomorphism.

When K is a compact Hausdorff topological space, the dual M(K) of C(K) is the space of in the sense of Bourbaki.see N. Bourbaki, (2004), "Integration I", Springer Verlag, . The subset P(K) of M(K) consisting of non-negative measures of mass 1 (probability measures) is a convex w*-closed subset of the unit ball of M(K). The of P(K) are the on K. The set of Dirac measures on K, equipped with the w*-topology, is to K.

The result has been extended by Amir and Cambern And to the case when the multiplicative Banach–Mazur distance between C(K) and C(L) is < 2. The theorem is no longer true when the distance is = 2.

In the commutative C(K), the maximal ideals are precisely kernels of Dirac measures on K, I_x = \ker \delta_x = \{f \in C(K) \mid f(x) = 0\}, \quad x \in K.

More generally, by the Gelfand–Mazur theorem, the maximal ideals of a unital commutative Banach algebra can be identified with its characters—not merely as sets but as topological spaces: the former with the hull-kernel topology and the latter with the w*-topology. In this identification, the maximal ideal space can be viewed as a w*-compact subset of the unit ball in the dual A'.

Not every unital commutative Banach algebra is of the form C(K) for some compact Hausdorff space K. However, this statement holds if one places C(K) in the smaller category of commutative C*-algebras. representation theorem for commutative C*-algebras states that every commutative unital C*-algebra A is isometrically isomorphic to a C(K) space.See for example

(1976). 9780387901763, Springer-Verlag.
The Hausdorff compact space K here is again the maximal ideal space, also called the spectrum of A in the C*-algebra context.


Bidual
If X is a normed space, the (continuous) dual X'' of the dual X' is called the ' or ' of X. For every normed space X, there is a natural map, injective.

For example, the dual of X = c_0 is identified with \ell^1, and the dual of \ell^1 is identified with \ell^{\infty}, the space of bounded scalar sequences. Under these identifications, F_X is the inclusion map from c_0 to \ell^{\infty}. It is indeed isometric, but not onto.

If F_X is , then the normed space X is called reflexive (see below). Being the dual of a normed space, the bidual X'' is complete, therefore, every reflexive normed space is a Banach space.

Using the isometric embedding F_X, it is customary to consider a normed space X as a subset of its bidual. When X is a Banach space, it is viewed as a closed linear subspace of X . If X is not reflexive, the unit ball of X is a proper subset of the unit ball of X. The Goldstine theorem states that the unit ball of a normed space is weakly*-dense in the unit ball of the bidual. In other words, for every x'' in the bidual, there exists a net (x_i)_{i \in I} in X so that


Banach's theorems
Here are the main general results about Banach spaces that go back to the time of Banach's book () and are related to the Baire category theorem. According to this theorem, a complete metric space (such as a Banach space, a Fréchet space or an ) cannot be equal to a union of countably many closed subsets with empty interiors. Therefore, a Banach space cannot be the union of countably many closed subspaces, unless it is already equal to one of them; a Banach space with a countable is finite-dimensional.

The Banach–Steinhaus theorem is not limited to Banach spaces. It can be extended for example to the case where X is a Fréchet space, provided the conclusion is modified as follows: under the same hypothesis, there exists a neighborhood U of \mathbf{0} in X such that all T in F are uniformly bounded on U, \sup_{T \in F} \sup_{x \in U} \; \|T(x)\|_Y < \infty.

This result is a direct consequence of the preceding Banach isomorphism theorem and of the canonical factorization of bounded linear maps.

This is another consequence of Banach's isomorphism theorem, applied to the continuous bijection from M_1 \oplus \cdots \oplus M_n onto X sending m_1, \cdots, m_n to the sum m_1 + \cdots + m_n.


Reflexivity
The normed space X is called when the natural map \begin{cases} F_X : X \to X'' \\ F_X(x) (f) = f(x) & \text{ for all } x \in X, \text{ and for all } f \in X'\end{cases} is surjective. Reflexive normed spaces are Banach spaces.

This is a consequence of the Hahn–Banach theorem. Further, by the open mapping theorem, if there is a bounded linear operator from the Banach space X onto the Banach space Y, then Y is reflexive.

Indeed, if the dual Y' of a Banach space Y is separable, then Y is separable. If X is reflexive and separable, then the dual of X' is separable, so X' is separable.

Hilbert spaces are reflexive. The L^p spaces are reflexive when 1 < p < \infty. More generally, uniformly convex spaces are reflexive, by the Milman–Pettis theorem. The spaces c_0, \ell^1, L^1(0,), C(0,) are not reflexive. In these examples of non-reflexive spaces X, the bidual X'' is "much larger" than X. Namely, under the natural isometric embedding of X into X given by the Hahn–Banach theorem, the quotient X / X is infinite-dimensional, and even nonseparable. However, Robert C. James has constructed an example of a non-reflexive space, usually called " the James space" and denoted by J,see , p. 25. such that the quotient J'' / J is one-dimensional. Furthermore, this space J is isometrically isomorphic to its bidual.

When X is reflexive, it follows that all closed and bounded of X are weakly compact. In a Hilbert space H, the weak compactness of the unit ball is very often used in the following way: every bounded sequence in H has weakly convergent subsequences.

Weak compactness of the unit ball provides a tool for finding solutions in reflexive spaces to certain optimization problems. For example, every continuous function on the unit ball B of a reflexive space attains its minimum at some point in B.

As a special case of the preceding result, when X is a reflexive space over \R, every continuous linear functional f in X' attains its maximum \|f\| on the unit ball of X. The following theorem of Robert C. James provides a converse statement.

The theorem can be extended to give a characterization of weakly compact convex sets.

On every non-reflexive Banach space X, there exist continuous linear functionals that are not norm-attaining. However, the theorem states that norm-attaining functionals are norm dense in the dual X' of X.


Weak convergences of sequences
A sequence \{x_n\} in a Banach space X is weakly convergent to a vector x \in X if \{f(x_n)\} converges to f(x) for every continuous linear functional f in the dual X'. The sequence \{x_n\} is a weakly Cauchy sequence if \{f(x_n)\} converges to a scalar limit L(f) for every f in X'. A sequence \{f_n\} in the dual X' is weakly* convergent to a functional f \in X' if f_n(x) converges to f(x) for every x in X. Weakly Cauchy sequences, weakly convergent and weakly* convergent sequences are norm bounded, as a consequence of the Banach–Steinhaus theorem.

When the sequence \{x_n\} in X is a weakly Cauchy sequence, the limit L above defines a bounded linear functional on the dual X', that is, an element L of the bidual of X, and L is the limit of \{x_n\} in the weak*-topology of the bidual. The Banach space X is weakly sequentially complete if every weakly Cauchy sequence is weakly convergent in X. It follows from the preceding discussion that reflexive spaces are weakly sequentially complete.

An orthonormal sequence in a Hilbert space is a simple example of a weakly convergent sequence, with limit equal to the \mathbf{0} vector. The unit vector basis of \ell^p for 1 < p < \infty, or of c_0, is another example of a weakly null sequence, that is, a sequence that converges weakly to \mathbf{0}. For every weakly null sequence in a Banach space, there exists a sequence of convex combinations of vectors from the given sequence that is norm-converging to \mathbf{0}.see Corollary 2, p. 11 in .

The unit vector basis of \ell^1 is not weakly Cauchy. Weakly Cauchy sequences in \ell^1 are weakly convergent, since L^1-spaces are weakly sequentially complete. Actually, weakly convergent sequences in \ell^1 are norm convergent.see p. 85 in . This means that \ell^1 satisfies Schur's property.


Results involving the basis
Weakly Cauchy sequences and the \ell^1 basis are the opposite cases of the dichotomy established in the following deep result of H. P. Rosenthal. Rosenthal's proof is for real scalars. The complex version of the result is due to L. Dor, in

A complement to this result is due to Odell and Rosenthal (1975).

By the Goldstine theorem, every element of the unit ball B of X is weak*-limit of a net in the unit ball of X. When X does not contain \ell^1, every element of B'' is weak*-limit of a in the unit ball of X.Odell and Rosenthal, Sublemma p. 378 and Remark p. 379.

When the Banach space X is separable, the unit ball of the dual X', equipped with the weak*-topology, is a metrizable compact space K, and every element x in the bidual X defines a bounded function on K: x' \in K \mapsto x (x'), \quad |x(x')| \leq \|x''\|.

This function is continuous for the compact topology of K if and only if x is actually in X, considered as subset of X. Assume in addition for the rest of the paragraph that X does not contain \ell^1. By the preceding result of Odell and Rosenthal, the function x'' is the pointwise limit on K of a sequence \{x_n\} \subseteq X of continuous functions on K, it is therefore a on K. The unit ball of the bidual is a pointwise compact subset of the first Baire class on K.for more on pointwise compact subsets of the Baire class, see .


Sequences, weak and weak* compactness
When X is separable, the unit ball of the dual is weak*-compact by the Banach–Alaoglu theorem and metrizable for the weak* topology, hence every bounded sequence in the dual has weakly* convergent subsequences. This applies to separable reflexive spaces, but more is true in this case, as stated below.

The weak topology of a Banach space X is metrizable if and only if X is finite-dimensional.see Proposition 2.5.14, p. 215 in . If the dual X' is separable, the weak topology of the unit ball of X is metrizable. This applies in particular to separable reflexive Banach spaces. Although the weak topology of the unit ball is not metrizable in general, one can characterize weak compactness using sequences.

A Banach space X is reflexive if and only if each bounded sequence in X has a weakly convergent subsequence.see Corollary 2.8.9, p. 251 in .

A weakly compact subset A in \ell^1 is norm-compact. Indeed, every sequence in A has weakly convergent subsequences by Eberlein–Šmulian, that are norm convergent by the Schur property of \ell^1.


Type and cotype
A way to classify Banach spaces is through the probabilistic notion of type and cotype, these two measure how far a Banach space is from a Hilbert space.


Schauder bases
A Schauder basis in a Banach space X is a sequence \{e_n\}_{n \geq 0} of vectors in X with the property that for every vector x \in X, there exist defined scalars \{x_n\}_{n \geq 0} depending on x, such that x = \sum_{n=0}^{\infty} x_n e_n, \quad \textit{i.e.,} \quad x = \lim_n P_n(x), \ P_n(x) := \sum_{k=0}^n x_k e_k.

Banach spaces with a Schauder basis are necessarily , because the countable set of finite linear combinations with rational coefficients (say) is dense.

It follows from the Banach–Steinhaus theorem that the linear mappings \{P_n\} are uniformly bounded by some constant C. Let \{e_n^*\} denote the coordinate functionals which assign to every x in X the coordinate x_n of x in the above expansion. They are called biorthogonal functionals. When the basis vectors have norm 1, the coordinate functionals \{e_n^*\} have norm {}\leq 2 C in the dual of X.

Most classical separable spaces have explicit bases. The \{h_n\} is a basis for L^p(0,) when 1 \leq p < \infty. The trigonometric system is a basis in L^p(\mathbf{T}) when 1 < p < \infty. The Schauder system is a basis in the space C(0,).see p. 3. The question of whether the disk algebra A(\mathbf{D}) has a basisthe question appears p. 238, §3 in Banach's book, . remained open for more than forty years, until Bočkarev showed in 1974 that A(\mathbf{D}) admits a basis constructed from the Franklin system.see S. V. Bočkarev, "Existence of a basis in the space of functions analytic in the disc, and some properties of Franklin's system". (Russian) Mat. Sb. (N.S.) 95(137) (1974), 3–18, 159.

Since every vector x in a Banach space X with a basis is the limit of P_n(x), with P_n of finite rank and uniformly bounded, the space X satisfies the bounded approximation property. The first example by of a space failing the approximation property was at the same time the first example of a separable Banach space without a Schauder basis.see

Robert C. James characterized reflexivity in Banach spaces with a basis: the space X with a Schauder basis is reflexive if and only if the basis is both shrinking and boundedly complete.see R.C. James, "Bases and reflexivity of Banach spaces". Ann. of Math. (2) 52, (1950). 518–527. See also p. 9. In this case, the biorthogonal functionals form a basis of the dual of X.


Tensor product
Let X and Y be two \mathbb{K}-vector spaces. The X \otimes Y of X and Y is a \mathbb{K}-vector space Z with a bilinear mapping T : X \times Y \to Z which has the following universal property:

If T_1 : X \times Y \to Z_1 is any bilinear mapping into a \mathbb{K}-vector space Z_1, then there exists a unique linear mapping f : Z \to Z_1 such that T_1 = f \circ T.

The image under T of a couple (x, y) in X \times Y is denoted by x \otimes y, and called a . Every element z in X \otimes Y is a finite sum of such simple tensors.

There are various norms that can be placed on the tensor product of the underlying vector spaces, amongst others the projective cross norm and injective cross norm introduced by A. Grothendieck in 1955.see A. Grothendieck, "Produits tensoriels topologiques et espaces nucléaires". Mem. Amer. Math. Soc. 1955 (1955), no. 16, 140 pp., and A. Grothendieck, "Résumé de la théorie métrique des produits tensoriels topologiques". Bol. Soc. Mat. São Paulo 8 1953 1–79.

In general, the tensor product of complete spaces is not complete again. When working with Banach spaces, it is customary to say that the projective tensor productsee chap. 2, p. 15 in . of two Banach spaces X and Y is the X \widehat{\otimes}_\pi Y of the algebraic tensor product X \otimes Y equipped with the projective tensor norm, and similarly for the injective tensor productsee chap. 3, p. 45 in . X \widehat{\otimes}_\varepsilon Y. Grothendieck proved in particular thatsee Example. 2.19, p. 29, and pp. 49–50 in .

\begin{align} C(K) \widehat{\otimes}_\varepsilon Y &\simeq C(K, Y), \\ L^1(0,) \widehat{\otimes}_\pi Y &\simeq L^1(0,, Y), \end{align} where K is a compact Hausdorff space, C(K, Y) the Banach space of continuous functions from K to Y and L^1(0,, Y) the space of Bochner-measurable and integrable functions from 0, to Y, and where the isomorphisms are isometric. The two isomorphisms above are the respective extensions of the map sending the tensor f \otimes y to the vector-valued function s \in K \to f(s) y \in Y.


Tensor products and the approximation property
Let X be a Banach space. The tensor product X' \widehat \otimes_\varepsilon X is identified isometrically with the closure in B(X) of the set of finite rank operators. When X has the approximation property, this closure coincides with the space of on X.

For every Banach space Y, there is a natural norm 1 linear map Y \widehat\otimes_\pi X \to Y \widehat\otimes_\varepsilon X obtained by extending the identity map of the algebraic tensor product. Grothendieck related the approximation problem to the question of whether this map is one-to-one when Y is the dual of X. Precisely, for every Banach space X, the map X' \widehat \otimes_\pi X \ \longrightarrow X' \widehat \otimes_\varepsilon X is one-to-one if and only if X has the approximation property.see Proposition 4.6, p. 74 in .

Grothendieck conjectured that X \widehat{\otimes}_\pi Y and X \widehat{\otimes}_\varepsilon Y must be different whenever X and Y are infinite-dimensional Banach spaces. This was disproved by in 1983.see Pisier, Gilles (1983), "Counterexamples to a conjecture of Grothendieck", Acta Math. 151:181–208. Pisier constructed an infinite-dimensional Banach space X such that X \widehat{\otimes}_\pi X and X \widehat{\otimes}_\varepsilon X are equal. Furthermore, just as example, this space X is a "hand-made" space that fails to have the approximation property. On the other hand, Szankowski proved that the classical space B(\ell^2) does not have the approximation property.see Szankowski, Andrzej (1981), "B(H) does not have the approximation property", Acta Math. 147: 89–108. Ryan claims that this result is due to , p. 74 in .


Some classification results

Characterizations of Hilbert space among Banach spaces
A necessary and sufficient condition for the norm of a Banach space X to be associated to an inner product is the parallelogram identity:

It follows, for example, that the L^p(0,) is a Hilbert space only when p = 2. If this identity is satisfied, the associated inner product is given by the polarization identity. In the case of real scalars, this gives: \langle x, y\rangle = \tfrac{1}{4}(\|x+y\|^2 - \|x-y\|^2).

For complex scalars, defining the inner product so as to be \Complex-linear in x, in y, the polarization identity gives: \langle x,y\rangle = \tfrac{1}{4}\left(\|x+y\|^2 - \|x-y\|^2 + i(\|x+iy\|^2 - \|x-iy\|^2)\right).

To see that the parallelogram law is sufficient, one observes in the real case that \langle x, y \rangle is symmetric, and in the complex case, that it satisfies the Hermitian symmetry property and \langle i x, y \rangle = i \langle x, y \rangle. The parallelogram law implies that \langle x, y \rangle is additive in x. It follows that it is linear over the rationals, thus linear by continuity.

Several characterizations of spaces isomorphic (rather than isometric) to Hilbert spaces are available. The parallelogram law can be extended to more than two vectors, and weakened by the introduction of a two-sided inequality with a constant c \geq 1: Kwapień proved that if c^{-2} \sum_{k=1}^n \|x_k\|^2 \leq \operatorname{Ave}_{\pm} \left\|\sum_{k=1}^n \pm x_k\right\|^2 \leq c^2 \sum_{k=1}^n \|x_k\|^2 for every integer n and all families of vectors \{x_1, \ldots, x_n\} \subseteq X, then the Banach space X is isomorphic to a Hilbert space.see Kwapień, S. (1970), "A linear topological characterization of inner-product spaces", Studia Math. 38:277–278. Here, \operatorname{Ave}_{\pm} denotes the average over the 2^n possible choices of signs \pm 1. In the same article, Kwapień proved that the validity of a Banach-valued Parseval's theorem for the Fourier transform characterizes Banach spaces isomorphic to Hilbert spaces.

Lindenstrauss and Tzafriri proved that a Banach space in which every closed linear subspace is complemented (that is, is the range of a bounded linear projection) is isomorphic to a Hilbert space. The proof rests upon Dvoretzky's theorem about Euclidean sections of high-dimensional centrally symmetric convex bodies. In other words, Dvoretzky's theorem states that for every integer n, any finite-dimensional normed space, with dimension sufficiently large compared to n, contains subspaces nearly isometric to the n-dimensional Euclidean space.

The next result gives the solution of the so-called . An infinite-dimensional Banach space X is said to be homogeneous if it is isomorphic to all its infinite-dimensional closed subspaces. A Banach space isomorphic to \ell^2 is homogeneous, and Banach asked for the converse.see p. 245 in . The homogeneity property is called "propriété (15)" there. Banach writes: "on ne connaît aucun exemple d'espace à une infinité de dimensions qui, sans être isomorphe avec (L^2). possède la propriété (15)".

An infinite-dimensional Banach space is hereditarily indecomposable when no subspace of it can be isomorphic to the direct sum of two infinite-dimensional Banach spaces. The dichotomy theorem asserts that every infinite-dimensional Banach space X contains, either a subspace Y with unconditional basis, or a hereditarily indecomposable subspace Z, and in particular, Z is not isomorphic to its closed hyperplanes.see If X is homogeneous, it must therefore have an unconditional basis. It follows then from the partial solution obtained by Komorowski and Tomczak–Jaegermann, for spaces with an unconditional basis,see and also that X is isomorphic to \ell^2.


Metric classification
If T : X \to Y is an from the Banach space X onto the Banach space Y (where both X and Y are vector spaces over \R), then the Mazur–Ulam theorem states that T must be an affine transformation. In particular, if T(0_X) = 0_Y, this is T maps the zero of X to the zero of Y, then T must be linear. This result implies that the metric in Banach spaces, and more generally in normed spaces, completely captures their linear structure.


Topological classification
Finite dimensional Banach spaces are homeomorphic as topological spaces, if and only if they have the same dimension as real vector spaces.

Anderson–Kadec theorem (1965–66) proves that any two infinite-dimensional Banach spaces are homeomorphic as topological spaces. Kadec's theorem was extended by Torunczyk, who proved that any two Banach spaces are homeomorphic if and only if they have the same density character, the minimum cardinality of a dense subset.


Spaces of continuous functions
When two compact Hausdorff spaces K_1 and K_2 are , the Banach spaces C(K_1) and C(K_2) are isometric. Conversely, when K_1 is not homeomorphic to K_2, the (multiplicative) Banach–Mazur distance between C(K_1) and C(K_2) must be greater than or equal to 2, see above the results by Amir and Cambern. Although uncountable compact metric spaces can have different homeomorphy types, one has the following result due to Milutin:Milyutin, Alekseĭ A. (1966), "Isomorphism of the spaces of continuous functions over compact sets of the cardinality of the continuum". (Russian) Teor. Funkciĭ Funkcional. Anal. i Priložen. Vyp. 2:150–156.

The situation is different for compact Hausdorff spaces. Every countably infinite compact K is homeomorphic to some closed interval of \langle 1, \alpha \rangle = \{ \gamma \mid 1 \leq \gamma \leq \alpha\} equipped with the , where \alpha is a countably infinite ordinal.One can take , where \beta + 1 is the Cantor–Bendixson rank of K, and n > 0 is the finite number of points in the \beta-th derived set K(\beta) of K. See Mazurkiewicz, Stefan; Sierpiński, Wacław (1920), "Contribution à la topologie des ensembles dénombrables", Fundamenta Mathematicae 1: 17–27. The Banach space C(K) is then isometric to . When \alpha, \beta are two countably infinite ordinals, and assuming \alpha \leq \beta, the spaces and are isomorphic if and only if .Bessaga, Czesław; Pełczyński, Aleksander (1960), "Spaces of continuous functions. IV. On isomorphical classification of spaces of continuous functions", Studia Math. 19:53–62. For example, the Banach spaces C(\langle 1, \omega\rangle), \ C(\langle 1, \omega^{\omega} \rangle), \ C(\langle 1, \omega^{\omega^2}\rangle), \ C(\langle 1, \omega^{\omega^3} \rangle), \cdots, C(\langle 1, \omega^{\omega^\omega} \rangle), \cdots are mutually non-isomorphic.


Examples

Derivatives
Several concepts of a derivative may be defined on a Banach space. See the articles on the Fréchet derivative and the Gateaux derivative for details. The Fréchet derivative allows for an extension of the concept of a to Banach spaces. The Gateaux derivative allows for an extension of a directional derivative to topological vector spaces. Fréchet differentiability is a stronger condition than Gateaux differentiability. The is another generalization of directional derivative that implies a stronger condition than Gateaux differentiability, but a weaker condition than Fréchet differentiability.


Generalizations
Several important spaces in functional analysis, for instance the space of all infinitely often differentiable functions \R \to \R, or the space of all distributions on \R, are complete but are not normed vector spaces and hence not Banach spaces. In Fréchet spaces one still has a complete , while are complete vector spaces arising as limits of Fréchet spaces.


See also

Notes

Bibliography
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